Proof of a q-Analog of a Constant Term Identity Conjectured by Forrester
نویسنده
چکیده
Proof: As in [Z], first use the Stembridge-Stanton trick, to transform (*) to the equivalent ”antisymmetric” version, let’s call it (*’), in which ( qxj xi )a is replaced by ( qxj xi ) a−1 , and the right side of (*) gets multiplied by (1− t)/(t; t)a. Next expand the very first product on the left of (*’), into a sum of 2 terms, and note that they are all bad guys (see [Z], p. 314 ), except for the n+ 1 terms x1...xry , r = 0, ..., n, the corresponding constant terms of which are evaluated by [Z]’s eq. (5.1). QED
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عنوان ژورنال:
- J. Comb. Theory, Ser. A
دوره 66 شماره
صفحات -
تاریخ انتشار 1994